0.5x^2+1.5-14=0

Solution for 0.5x^2+1.5-14=0 equation:

0.5x^2+1.5-14=0

We add all the numbers together, and all the variables

0.5x^2-12.5=0

a = 0.5; b = 0; c = -12.5;
Δ = b2-4ac
Δ = 02-4·0.5·(-12.5)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-5}{2*0.5}=\frac{-5}{1}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+5}{2*0.5}=\frac{5}{1}
=5
$